N:=98;
M:=9;
AAC1:=MA((2*CLOSE+HIGH+LOW)/4,5);
支撑11:=AAC1*(200-N)/100;
CCD1:=ABS((2*CLOSE+HIGH+LOW)/4-MA(CLOSE,20))/MA(CLOSE,20);
DDC1:=DMA(CLOSE,CCD1);
支撑12:=(1-M/100)*DDC1;
黄金坑:C>支撑12 AND C/REF(C,1)>1.02 AND CROSS(REF(支撑12,1),REF(C,1))
AND REF(C,1)<REF(支撑11,1);
